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Beinhaltet die Namen: TOM APOSTOL, T.M. Apostol, Tom M. Apostol, Tom M. Apostol

Beinhaltet auch: Hyman (3)

Bildnachweis: Tom Mike Apostol

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Mathematical Analysis (1957) 191 Exemplare
Calculus (1962) 51 Exemplare
Essential Calculus Volume 1 (2014) 2 Exemplare
Calculas 1 Exemplar

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Continuación del Calculus volumen I, segunda edición. Presenta un enfoque hacia la técnica y un riguroso desarrollo teórico
 
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hernanvillamil | 1 weitere Rezension | Dec 27, 2019 |
La disposición de este libro ha sido sugerida por el desarrollo histórico y filosófico del cálculo y la geometría analítica
 
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hernanvillamil | 2 weitere Rezensionen | Dec 26, 2019 |
El libro constituye una transición del cálculo elemental a cursos más avanzados de la teoría de funciones real y compleja. Introduce el pensamiento abstracto que ocupa el análisis moderno
 
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hernanvillamil | Dec 17, 2019 |
Where are the zeros of zeta of s?
G.F.B. Riemann has made a good guess;
They’re all on the critical line, saith he,
And their density’s one over 2pi log t.
This statement of Riemann’s has been like a trigger
And many good men, with vim and with vigor,
Have attempted to find, with mathematical rigor,
What happens to zeta as mod t gets bigger.

The efforts of Landau and Bohr and Cramer,
And Littlewood, Hardy and Titchmarsh are there,
In spite of their efforts and skill and finesse,
In locating the zeros there’s been little success.
In 1914 G.H. Hardy did find,
An infinite number that lay on the line,
His theorem however, won’t rule out the case,
There might be a zero at some other place.
Let P be the function of pi minus li,
The order of P is not known for x high,
If square root of x times log x we could show,
Then Riemann’s conjecture would surely be so.
Related to this is another enigma,
Concerning the Lindelof function mu (sigma)
Which measures the growth in the critical strip,
On the number of zeros it gives us a grip.
But nobody knows how this function behaves,
Convexity tells us it can have no waves,
Lindelof said that the shape of its graph,
Is constant when sigma is more than one-half.
Oh, where are the zeros of zeta of s?
We must know exactly, we cannot just guess,
In order to strengthen the prime number theorem,
The integral’s contour must not get too near ‘em.
… (mehr)
 
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ElizabethMurg | Oct 15, 2015 |

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